| 网站首页 | 考试学习 | 英语学习 | 求职 | 资源下载 | 出国留学 | 论文中心 | 箐箐校园 | 
资格类考试: 公务员考试 报关员考试 导游资格 注册会计 司法考试
外语类考试: 英语四六级 雅思 托福 GRE BEC PETS 职称英语
学历类考试: 高考 考研 自考 成考 专升本
计算机考试: 等级考试 水平考试 微软认证 思科认证 Linux认证
设为主页
联系站长
添加收藏夹
您现在的位置: 学子考试网 >> 考试学习 >> IT考试 >> 思科认证 >> 试题中心 >> 文章正文 用户登录 新用户注册
特 别 推 荐
· 报关员辅导
· 经济师辅导
· 会计职称辅导
· 注册会计师辅导
· 英语四级辅导
· 公共英语(PETS)辅导
· 商务英语(BEC)辅导
· 职称英语辅导
· 报检员辅导
· 造价工程师辅导
· 2006公务员网络辅导课程
· 查看更多...
最 新 热 门
最 新 推 荐
相 关 文 章
  • CiscoCCNA考试七十九题

  • 网管学堂:Trunk(端口汇聚

  • CCNA考试实验常用的命令总

  • CiscoCCNA考试56题 【字体:
    http://www.ks263.com 来源:ks263.com 点击数: 更新:2006-7-24 【VIVI收藏

     

    C The Data Circuit-terminating Equipment (DCE) is responsible for providing the clocking on the wire. HINT: When You see the ’C’ in ’DCE’, think ’Clocking’ 

    33. How do you set the encapsulation type to PPP for an interface? A.) ppp ietf B.) encapsulation ppp C.) ppp enable D.) ppp cisco E.) enable ppp 

    34 What would the command ’TERMINAL NO EDITING’ do? A.) Nothing. B.) Turn exec mode off. C.) Prevent terminal configuration. D.) Turn off enhanced editing. E.) Prevents update to RAM. 

    35 How do you view the routers current processor utilization? A.) show cpu B.) show startup-config C.) show version D.) show utilization E.) show running-config F.) show processes cpu 

    F Router#sh processes cpu CPU utilization for five seconds: 2%/2%; one minute: 1%; five minutes: 0% 

    36 Which Standard IP Access list commands will deny only the source address 1.1.1.1? A.) access-list 9 permit 1.1.1.1 255.255.255.0 B.) access-list 9 permit any C.) access-list 9 deny 1.1.1.1 0.0.0.0 D.) access-list 9 permit 1.1.1.1 0.255.255.255 E.) access-list 9 deny 1.1.1.1 255.255.255.255 

    C A 0.0.0.0 wildcard mask means check every bit and make sure that it matches. For our example, the IP host address 1.1.1.1 is a specific address to check on the network. An alternative would be to use the IP network address and a special access-list wildcard mask to check an entire subnetwork. 

    37 What should be the first command to create an extended access-list that denies host 1.1.1.1 from telnetting anywhere? A.) access-list 10 deny tcp host 1.1.1.1 any eq 20 B.) access-list 10 deny tcp host 1.1.1.1 any eq 22 C.) access-list 10 deny tcp host 1.1.1.1 any eq 23 D.) None of the above are correct. E.) access-list 10 deny tcp host 1.1.1.1 any eq 24 F.) access-list 10 deny tcp host 1.1.1.1 any eq 21 

    D This was a trick question. Extended access-lists for TCP/IP must be in the range 100-199. Watch those access-list numbers! 

    38 There are 2 types of PPP authentication supported by the Cisco IOS. What are they? (2 Answers) A.) STACKER B.) CHAP C.) Kermit D.) PREDICTOR E.) PAP F.) MD5 

    B E 

    39 What type of switching creates variable latency through the switch? A.) Multiplexed B.) Cut-Through C.) Layer 4 D.) Store and Forward E.) Inverted 

    D DEFINITION: Latency = Delay.Because a store and forward switch reads the whole frame before forwarding, a larger frame takes longer than a shorter frame. 

    40. Given the global configuration commands: ’banner motd #’ ’Hello #’ When would the message be displayed? A.) Message of the day banners are not possible. B.) The message of the day banner shows up before login. C.) These commands are not the right syntax for MOTD. D.) Message of the day banners are displayed upon entering global config mode. E.) The message of the day banner shows up during logoff. F.) The message of the day would be, ’Hello #’ 

    41 Which command enables frame relay on a router’s interface? A.) map wan type=7 B.) encapsulation frame-relay C.) frame-relay enable D.) interface frame-relay E.) cisco encap F.) enable frame-relay 

    42 Which subnet is the host 200.1.1.99 /27 on? A.) 200.1.1.0 B.) 200.1.1.96 C.) 200.1.1.128 D.) 200.1.1.64 E.) 200.1.1.16 


    B The shorthand notation /27 = 3 bits in the last octet = decimal 255.255.255.224 Shortcut: 256 - 224 = 32. Valid subnets are multiples of 32 (32,64,96,128, etc). Shortcut #2: Because it’s a small slice and a big number, who wants to count up every 32 digits to find the next subnetwork address? Just divide 99 / 32 = 3 times. Now, take 3 x 32 slices = 96, so 99 is on the network 96. 

    上一页  [1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13] [14] [15] [16] 下一页  

    文章录入:ks263.com    责任编辑:ks263.com 
  • 上一篇文章:

  • 下一篇文章: 没有了
  • 发表评论】【加入收藏】【告诉好友】【打印此文】【关闭窗口